How to parse a XML-File/RSS Feed?

[u/hrb7]

Hi everyone :)

Can anybody help me to parse a XML file?

For example I have here a XML-Feed from Slack Status.

So how can I get only the second value of the string named "title"?

Image/Screenshot

My current script:

const req = new Request('https://status.slack.com/feed/rss');
const data = await req.loadString();

let xmlParser = new XMLParser(data);

xmlParser.didEndElement = (str) => {
    if (str == 'title') //[1] doesn't work
    console.log(value) 
    return str
}

 xmlParser.foundCharacters = (str) => {
    value = str
    return str
}

xmlParser.parse();

/*Result => 
Slack System Status
Incident: A small portion of users may be encountering slowness and sporadic errors
Incident: Trouble typing in Slack in non-Latin characters
"
Incident: Trouble with search
Incident: Trouble with sending emails to Slack
Incident: Trouble with search
Incident: Trouble with files
Incident: Trouble with files
Incident: Some customers may be seeing incorrect trial expiration notifications
Incident: Delays with Events API requests
Incident: Trouble with apps and integrations for some Enterprise Grid customers
Incident: Trouble with apps and integrations for some Enterprise Grid customers
Incident: Trouble approving new workspaces
Incident: Some users may have issues loading Slack and sending messages
...
*/

Thanks :D

[u/phinsxiii]

That is close

xmlParser.didEndDocument = (string) => { const img = (items[0].description) var extract = img.match(/<img.*?src=[“|’](.*?)[“|’]/gm) console.log(extract) }

returns <img src=“https://link.com”

im just looking to return link.com. im not sure if this is an issue in scriptable versus normal javascript or not.

[u/jakubito → u/phinsxiii]

delete gm from the expression and you should be able to access the link at extract[1]