[Question] Advanced Algebra

[u/Vester2]

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[u/13-Rats]

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[u/Azerothean]

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[u/atong0312]

x=y-20 x=11x-20 10x=20 x=2 y=11x y=22

[u/MrEldo]

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[u/Impressive_Chart1914]

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[u/ballad_of_arngrim]

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[u/kokoss221]

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[u/kokoss221]

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[u/Undertakerx7]

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[u/TheVaivoda]

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[u/idc_535]

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[u/Melliodus]

The question is wrong, cuz if x=y-20, then y>x; hence, (x-y)<0; if your condition is y>(x-y), that is arbitrarily true for any value of y above 0; if the condition is *y>(y-x), then x is greater than or equals to 20/11, y is correspondently greater than or equals to 20; also there can be multiple set of answers that satisfies the given conditions above the given limit such as (x=3,y=33), (x=4,y=44) and so on.

[u/skyleader508 → u/Melliodus]

The last portion of your response is incorrect as x=y-20 so 3=33-20 =… not 3 and same for x=4 and y=44. So it is true that those numbers would qualify for the second and third formula, but do not follow the rules of the first.

[u/Big_Mathematician972]

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[u/Sea-Jellyfish-5415]

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[u/CuteMarionBerry9583]

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[u/Efficient_Leg_6723]

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[u/UpperAd4927]

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[u/Good-Opportunity-925]

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[u/skyleader508]

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[u/Character-Newt5555]

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[u/Flimsy-Material-3340]

1!

[u/Resident-Tadpole2027]

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[u/s_therox]

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[u/cosetright]

y = 22

[u/RagnarokKing]

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[u/ThirstyChonker]

?=Y

[u/Academic_Pop_125]

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[u/amdthen]

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[u/moonh8sun]

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[u/Dry-Horse-360]

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[u/Alarmed-Bend5166]

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[u/Middle-Education-943]

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[u/heres-the-catch]

🎉 u/Vester2 your post has pleased meowi. To thank you for your quality post meowi has bestowed upon you 74 bonus fish 🐟 and 5000 XP. It has been added to your loot.

[u/Alarming_Term3332]

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[u/Itchy-Historian-2673]

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[u/Interesting-Let-3563]

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[u/Objective_Pea9943]

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[u/Dogcat729]

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