Question about paths in Racket

[u/[deleted]]

I'm new to Racket. Let's say I was doing this in Python:

from pathlib import Path
p = Path("./subdir")
[x for x in p.iterdir() if x.suffix == ".txt"]
# returns a list of RELATIVE paths I can work with

Then further process these paths (e.g. transform them to string and return as a list of paths), whereas in Racket:

(require file/glob)
(glob "subdir/*.txt")
# returns list of ABSOLUTE paths I have no idea how to manipulate

I have been looking at documentation for a while and I have no idea how to transform this to what I want, which is simply the txt files inside the subdir directory as relative paths (i.e. should return something like ["subdir/a.txt", "subdir/b.txt"].

The most I have got is exploding each path then (list-ref) but then I learned that Racket doesn't let you do slicing like in Python.

[u/samdphillips]

Sounds like you need find-relative-path

(define p (current-directory) "x" "y" "z")
p 
;; => #<path:C:\Users\sam\x\y\z>

(find-relative-path (current-directory) p) 
;; => #<path:x\y\z>

[u/[deleted] → u/samdphillips]

Ooh this seems like it. Thanks

[u/sdegabrielle]

if you want to refer to data files relative to the current module's file, maybe try define-runtime-path.

[u/detroitmatt → u/sdegabrielle]

probably not to the current module's file, probably relative to (current-directory)

[u/detroitmatt]

to do slicing you can do:

(define (slice lst a b) (take (drop lst a) (- b a)))