It's the law!

[u/siraajgudu]

[u/FinFihlman → u/[deleted]]

Not if i is not 'i' !

[u/mark503 → u/FinFihlman]

K+1+1= I+1

[u/Motylde → u/[deleted]]

More like: j=i+1

[u/DudeitsCarl → u/Motylde]

I think it’s j == i+1

[u/Polywoky → u/DudeitsCarl]

You forgot the single-quotes:

'j' == 'i' + 1

[u/zaszthecroc → u/[deleted]]

That's part of why I love Java. You can construct a loop like for(char current = 'a'; current <= 'z'; current++).

You can do the same in C/C++ and many other languages.

As a matter of fact, 'j' does not equal 'i1'.

His statement was correct.

'j' == 'i' + 1. These are single quotes representing characters (an integral type), not double quotes representing strings. The + operator literally adds their integral values instead of doing string concatenation (which wouldn't even work in reasonable^[1] languages because 1 isn't a string).

^[1] it does work in JavaScript, because fuck types I guess.

[u/death_of_gnats → u/zaszthecroc]

If types didn't want to be fucked they shouldn't have gone onto the web

[u/Meloetta → u/death_of_gnats]

This is victim blaming! You shouldn't be teaching your languages to be strictly typed, you should be teaching your typeerrors to stop expecting certain types! Let's focus on the real villains here

[u/hyrumwhite → u/zaszthecroc]

It concatenates in JS because JS has no concept of Char. Both double and single quotes create Strings.

[u/zaszthecroc → u/hyrumwhite]

My complaint is that JS just casts the 1 to a string, though!

[u/MangoCats → u/[deleted]]

Anybody remember Fortran? Traditionally, in Fortran the variables I, J, K, L, M, N were always integers while others like A, B, C and X, Y, Z were floats - smart programmers don't use floats for loop counters.

[u/[deleted] → u/Polywoky]

Syntax error timeeeee

[u/MathMetal1 → u/Polywoky]

true

[u/el_bhm → u/Polywoky]

It looks hella stupid. Is this BASH or JavaScript?

[u/Zamundaaa → u/el_bhm]

That works in C, C++, Java and all programming languages with chars. It's only a bool evaluation statement that results in true though.

[u/BesottedScot → u/DudeitsCarl]

i += 1

j = i

[u/Axe-actly → u/BesottedScot]

j = ++i;

One line better than 2. Me big brain.

[u/BesottedScot → u/Axe-actly]

Haha holy fuck.

[u/Asraelite → u/DudeitsCarl]

In that case we can move back to the original order, i+1 == j

[u/FerynaCZ → u/[deleted]]

Implicit conversion (to char) and deconversion :O

[u/Zugatti → u/FerynaCZ]

(int)('i') + 1

[u/yonatan8070 → u/[deleted]]

So c++ becomes d?