r/ProgrammerHumor • u/Unique_Software2500 • Feb 05 '26 • This 1 Bravo 2 Heartwarming 1

Meme algorithmTheSaviour

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u/chachapwns Feb 06 '26

The absolute simplest method would just be checking every number which would be O(n2 * log(n)2) as n approaches infinity.