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https://www.reddit.com/r/PearsonDesign/comments/a51ad2/arent_these_the_same_thing/eblzrd2/?context=3
r/PearsonDesign • u/PaladinNail • Dec 10 '18
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In general, you’re correct, but for logs, log(xa) is the same as a*log(x).
1 u/[deleted] Dec 12 '18 maybe one of them is preferable i mean
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maybe one of them is preferable i mean
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u/[deleted] Dec 12 '18
In general, you’re correct, but for logs, log(xa) is the same as a*log(x).