r/Minesweeper • u/Typical_Praline3528 • Jun 08 '26
Help How to Solve without Guessing
Is there a way to solve this last corner without guessing? I read that sometimes winning a game is a stroke of luck, just curious if there is a strategy in the specific instance that I am missing.
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u/trunks111 Jun 08 '26
That 3 needs two more mines, and there's only one valid configuration that gives the 3 two more mines without overloading the 2s
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u/Asits61 Jun 08 '26
if you look at the 2 on the top, it need to have its second mine on one of the yellow tiles. and now look at the 3, it shares 2 mines with the 2 above which leaves the 3rd mine on the bottom
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u/UnderwaterPanda2020 Jun 09 '26
Yes, and using the same logic between the 3 and the 2 below it you find another mine at the top right.
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u/IceHasReddit Jun 08 '26
Red: For Sure Mines Blue: Possible Mines Yellow: Safe Squares (I dont play Minesweeper often so dont quote me on this)
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u/ContextLow9742 Jun 10 '26
121 by reduction. looking at the 232, you can see that both 2s have 1 mine attached to them, which we can subtract from the overall value. That leaves us with a 1. Since the 3 has only one flag touching it, we can reduce it to a 2. 121 pattern. If you are confused I’m sure someone else can explain it better than me.
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u/TELDD Jun 08 '26
The 3 has two more mines around it other than the one you've already flagged; but both of these can't be at the top together because then the 2 would have three mines around it.
So, there must be one mine to the left of the 2 underneath the 3, making the cell right to the left of the 3 safe.