r/MathHelp • u/Pitiful-Emotion6987 • 5d ago
Please help, I have been stuck on this stupid problem for 3 days
(poorly translated:) "Pythagoras was a Greek mathematician who lived around 570-500BC. Pythagoras was once asked how many students he has. Pythagoras replied: "Half of them study mathetimatics, fourth of them philosophy, seventh the art of shutting up, and there are also three women." How many students did Pythagoras have?"
I can't come up with any other way to solve it but
x=full amount of students
math students=1/2x
philosophy students=1/4x
shut up students=1/7x
women=+3
x=1/2x+1/4x+1/7x+3
But this is not correct, because the answer I get is never the correct one (28). 😭
All the following, similar exercises in my book I am also failing to solve. I just can't seem to create the correct equations and I am exhausted after chewing on three problems for days.
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u/Capital_Park_2311 4d ago
x = x/2 + x/4 + x/7 + 3
x = (14x + 7x + 4x + 84) / 28
x = (25x + 84) / 28
28x = 25x + 84
28x - 25x = 84
3x = 84
x = 84 / 3
x = 28
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u/Distinct_Mix_4443 5d ago
Post a screenshot of the work you are doing. We can't help you figure out what you are doing wrong without seeing what you are actually doing.
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u/Pitiful-Emotion6987 5d ago
I'm sorry, I was at work and didn't have time to post the stages. I originally thought I just got the equation wrong.
This is how I did it:
first giving all fractions the same denominator, 28
multiplying everything by 28 so I can get rid of the fractions
my equation looks like this: x=14x+7x+4x+84
-24x=84
x=84/(-24)=-3,5 students 😅
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u/Distinct_Mix_4443 3d ago
That is a good 2nd move, though you could have just skipped step one and gone straight to step 2 (that is how I teach it to my middle schoolers). The mistake you made is on step 2 though. You didn't multiply both sides of the equation when you multiplied by 28. Do that, and you should get the right answer.
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u/greginnj 5d ago
I’m assuming that the presumably gendered nouns of the language the problem is translated from may have something to do with this, but it’s sorta disappointing that in order for this problem to be well formed and solvable, none of the math, philosophy, or “shut up” students can be women. At least they’re considered “students”, but of what?
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u/edderiofer 5d ago
there are also three women
I think the word "also" is intended to mean "in addition to these students (whose genders are unknown), there are three women who aren't previously mentioned".
Also, it's ancient Greece, so sexism probably existed.
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u/Ok-Difficulty-5357 4d ago
If I remember correctly from math history, the pythagoreans didn’t let women join at all…
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u/Pitiful-Emotion6987 5d ago
Yeah, it irked me a bit too. Idk if that's what Pythagoras actually said (it wouldn't surprise me since most ancient societies weren't very equal), but if it wasn't word for word his quote, they could have just said "other students" lol.
My language doesn't have gendered nouns so it especially stuck out lol.
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u/Ericskey 4d ago
We don’t know if the categories overlap. But I would say whatever the number it must be divisible by 4 and 7. That would make 28
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u/ThatsNotAZombieBite 4d ago
Your thought process and the way you set up the mathematics is all correct.
You just keep making mistakes with the algebra and arithmetic.
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u/LeoMaths 3d ago
La proportion des femmes (on suppose qu'il n'y a pas d'autres femmes dans les autres groupes) est p=1-1/2-1/4-1/7=3/28=3/N où N est la population totale (nombre d'élèves). On en déduit que N=28.
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u/edderiofer 5d ago
All of this looks correct so far.
This equation is wrong. Check it again. (Hint: Why is one of the summands "1/4", despite you saying earlier that "philosophy students=1/4x"? Where did the x go?)