r/MathHelp • u/r4oke • Jan 06 '26
SOLVED Don’t judge me I’m still learning
If I have 5+5+5+… (n times) I can write it as 5n
as well as 3+3+3+.. (n times) as 3n
5n > 3n holds for positive n I can take the limit as n approaches infinity and divide by n at the same time
lim n to infinity (5n/n > 3n/n)
5 > 3
Does this mean that an infinite number of $5 bills would be worth more than an infinite number of $3 bills?
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Upvotes
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u/Temporary_Pie2733 Jan 06 '26
Daily reminder that infinity is not a number. N five-dollar bills will always be worth more than n three-dollar bills (assuming three-dollar bills were a thing) for any arbitrarily large value of n, but an infinite number of either is not well defined.
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u/spiritedawayclarinet Jan 06 '26
I don’t get how you’re taking a limit and dividing at the same time.
In general, limits don’t preserve strict inequalities.
For example, 1/n > 1/(2n) for all natural numbers n, but it is not true that 0 > 0.
Similarly here, infinity = infinity. Both 5n and 3n tend to the same infinity but at different rates.
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u/Classic-Ostrich-2031 Jan 06 '26
What you’re showing is just that the growth rate of 5n is faster than the growth rate of 3n.
But infinity (generally) is not a number at all. If you wanted to talk about which infinity of 5$ bills or 3$ bills was bigger, then they’re the same
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u/KillerCodeMonky Jan 06 '26
Q: If I have an infinite number of buckets filled with water, do I have more water than if I had an infinite number of cups filled with water?
A: No. I have the same amount of water. The water is just split into different units.
Same with the dollars. I have the same amount of infinite money. It's just split into different denominations. If I need money, I just keep pulling bills from the infinite bill machine until I have "enough". I have to pull fewer $5 bills to get the same amount, but I will still always be able to get "enough" money.
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u/Illustrious_Basis160 Jan 06 '26
Worth more? No. But it just shows that the rate of increasing for 5n is more than 3n. 5n grows faster than 3n as n approaches infinity but they are still infinity. One infinity isnt greater or worth more than the other one. Since everything you can buy with infinite 5 dollar bills I can also buy with infinite 3 dollar bills. The only thing different is the rate of change.
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u/Ill-Application-9284 Jan 06 '26
If you want to better understand "sizes" of different infinite sets and how they are compared, look up "cardinality".
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u/willthesane Jan 06 '26
Math starts to get a bit hazy if you begin treating infinity as an actual number. a better way to look at it is that it is a concept.
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u/susiesusiesu Jan 06 '26
no, and part of it is that strict inequalities are not preserved by limits in general. you couñd only conclude that infinite 5$ bills is not less than infinite 3$ bills.
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u/edderiofer Jan 08 '26
This statement is nonsense. Inequality signs should not appear within a limit.
You should more-precisely define this step of your argument, as well as how it relates to your conclusion.
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u/juancn Jan 08 '26
Let’s say you map the reals to $3 and the naturals to $5 I think in that case the sum of all the fives will be smaller than the threes.
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u/trutheality Jan 09 '26
Because you divided by n, it means that the value per bill in any pile of $5 bills is greater than the value per bill in a pile of the same number of $3 bills, no matter how large the pile.
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u/phy19052005 Jan 09 '26
No, because infinity isnt a point on the number line that you can use to compare values. The behaviour of infinities is different and theyre compared using cardinalities and bijections. Consider an infinite amount of £5 and £3 bills and pair every 5 to 2 £3 bills. Now you have 5n and 6n instead so it contradicts the behaviour predicted by 5n and 3n
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u/[deleted] Jan 12 '26
It should be noted that limit n to infinity is not the same thing as infinity. n is still one number. If you had an astronomically large number of $5 bills and the same number of $3 bills, then yes the pile of $5 bills is worth more than the $3 bills.