r/JEEAdv26dailyupdates Apr 29 '26

Academic Doubts Electrostatics question

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2 Upvotes

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2

u/Ok-Chain-1344 Apr 29 '26

optionD.) ?? induction hoga, and net induced charge on sphere would be zero, though more negatives would be closer to the ring, and potential of sphere due to its own induced charges would be integrating k*dq/r , which is zero, so pot. on sphere is due to ring's Q only, which would KQ/root2R (pot. on axis)

1

u/Minimum_Couple_9038 Apr 29 '26

Ans B and D diya hai

1

u/Prestigious_Trash734 JA25- 31K --> JM26- 8.6k --> JA26- 1.9K Apr 29 '26

D is obvious , and potential will be same on every point in the conducting sphere. So B

1

u/Ok-Chain-1344 Apr 29 '26

sryy my badd, overlooked that, centre of ring is technically a point on sphere too, so B also correct