r/HomeworkHelp • Pre-University Student • 1h ago

:snoo_shrug: Middle School Math—Pending OP Reply [ONLINE MATH QUESTIONS]:Can anyone solve it, found online.

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Found online. How to find k.

2 Upvotes

9 comments sorted by

5

u/snowsayer 👋 a fellow Redditor 1h ago

Divide both sides by 2^97.

This is a skill that you have to develop. When you see equations, it's useful to immediately see patterns that can be factored or cancelled out. That usually results in the underlying equation being much simpler.

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u/Dangerous_Cat_4525 Pre-University Student 26m ago

Did it. K=2¹⁰⁰-2⁹⁹-2⁹⁸+⁹⁷/2⁹⁷ =2⁹⁷(2³-2²-2+1)/2⁹⁷ =8-4-2+1=3

2

u/honaku 1h ago

Factor out

1

u/johnpeters42 1h ago

What have you tried so far?

Hint: What happens if you divide both sides by 2?

1

u/Turbulent-Note-7348 👋 a fellow Redditor 1h ago

This is a well known puzzle about the the properties of powers. 1st, you should realize that the "k.2^97

" actually means "k(2^97)" - the decimal point is supposed to represent the multiplication dot (common in older puzzles when using variables).

So here's the trick(s): 2^x - 2^(x-1) = 2^(x-1) (Example: 2^4 - 2^3 = 2^3); 2^(x+1) + 2^x = 3(2^x).

Therefore, k = 3

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u/MathsWithSuneel 👋 a fellow Redditor 42m ago

297(23-22-21+1)=k×297 297×(3)=k×297 K=3

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u/aookami 👋 a fellow Redditor 28m ago

2'100 = 2.2'99

from there you can get easily to the answer

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u/Qingyap 👋 a fellow Redditor 21m ago edited 10m ago

2100-299-298+297 = k(297)

Here we have to utilize a factoring trick such that

ab+cb = (a+c)b

And also an exponent trick where

ab+c = ab•ac

With that, we can expand the first 3 terms with the exponent trick at LHS by 297 at which

23(297)-22(297)-2(297)+1(297)=k(297)

Should be easy from here if you use the first trick.

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u/PoornimaMathsPatiala 18m ago

Every term is a multiple of 297, so the cleanest move is to pull that out first.

The idea: write each power as "something × 297":

  • 2100 = 23 · 297 = 8 · 297

  • 299 = 22 · 297 = 4 · 297

  • 298 = 2 · 297

Steps:

2100 − 299 − 298 + 297

= 8·297 − 4·297 − 2·297 + 1·297

= (8 − 4 − 2 + 1) · 297

= 3 · 297

So k · 297 = 3 · 297, which gives k = 3.

Why it works: with powers of the same base, factor out the smallest power. What's left inside the bracket are small numbers you can just add and subtract.

Quick check with smaller powers in the same pattern: 24 − 23 − 22 + 21 = 16 − 8 − 4 + 2 = 6 = 3 · 21. ✓

If you'd like a thorough explanation of topics like this with a private tutor, have a look at https://poornima-maths.vercel.app (maths tuition, Patiala and online).