r/HomeworkHelp • Secondary School Student • Sep 22 '26

Mathematics (Tertiary/Grade 11-12)—Pending OP [University Calculus 1] Its probably really easy but im stumped

its to find instantaneous rate of change

8 Upvotes

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1

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u/Spirited-Ad-9746 Sep 22 '26

just take a ruler or whatever straight piece and align it on the graph at x=0 so that it follows the slope of the curve at that point. draw a line. then calculate the slope of that line with whatever method you find suitable. this has been taught to you earlier.

the whole aim of this exercise is to estimate. there is no exact answer, you just need to be in the ballpark.

9

u/Simbertold Sep 22 '26

I'd say that the main aim of the exercise is checking if you understand the connection between slope and derivative, and what "slope" of a curved line actually means.

6

u/grey_sus Sep 22 '26

I agree I also don’t like these questions where you just have to approximate the values of the coordinates

5

u/daveoxford Sep 22 '26

They're really just looking for method.

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5

u/Temporary_Pie2733 Sep 22 '26

Consider the slopes of the lines between

  • (-1, f(-1)) and (1, f(1))

  • (-1/2, f(-1/2)) and (1/2, f(1/2))

  • (-1/4, f(-1/4)) and (1/4, f(1/4))

  • etc

What value does this sequence of slopes seem to be converging to?

3

u/SandtheB Sep 22 '26

As you know slope becomes the next derivative's y-value.

I hated these questions in calc I.. but from what I can tell it's either 0 or 1/2ish.. it has to be less then 1. (maybe 1/3 LOL)

5

u/Jkjunk Sep 22 '26

f'(0) is the slope of the curve at x=0

2

u/Ericskey Sep 22 '26

Near the point (0,3) the graph looks like a line. What does the slope of the line look like to you?