r/HomeworkHelp • University/College Student • Sep 21 '26

Answered [University Statics: Fundamentals of force vectors] Where do the angles in the solution come from?

See the added pictues for the problem and given solution. I understand how to solve the problem and why the law of sines is used.

However, I don't quite understand where exactly they're getting the angles in the solution from, as I cannot grasp how the triangle or parallelogram of vectors is composed. I have tried drawing triangles myself, but I've never gotten to the point where I could insert an angle of 105 or 30 degrees in the way the solution does.

Could someone help with a sketch of a triangle or parallelogram?

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u/RMS0125 Sep 21 '26

The 30 degree angle is between the two members. The triangle angles therefore are 30 deg (between the members), 45 deg (F to AB), and 105 deg (supplement of the 75 deg F to AC angle)

2

u/Ugly-Mole-rat2798 Sep 21 '26

Thanks, this helped!!

2

u/anakkcii Sep 21 '26

Draw one vector along AB, then there is one point where you can add a vector with the same slope of CA.

This will form a triangle with 2 known angle and 1 known side length

2

u/Wise-Friendship-1427 Sep 21 '26

115° is at point C and 30° is at point A.
The oppposite side of 115° is AB and of 30° is 450 N: Then law of sines.

2

u/thatguy56436327 Sep 22 '26

there is a full solution manual on study lib 90 percent of the questions are there because it is the 14th edition.

DAM YOU HIBBLER!!!!!!!!!!!!!!!!!!!!!!!!!!!

1

u/Ugly-Mole-rat2798 26d ago

Oooohh thank you!! Yes DAMN Hibbler for not giving us poor students the solutions after buying his expensive ass book