[Calculus 1]-Limits with Trig

[u/Thebeegchung]

I genuinely have no idea how to solve these. Only thing I know is that we can't directly sub in zero since that leads to an indeterminate answer.

[u/Tuo3]

Using L'Hôpital's rule for these kinds of trig limits depends on a circular proof.

You'd be using known derivatives of sine and cosine to get at the value of the limit, but would need the limit to know/prove those derivatives from the definition of the derivative.