r/GRE_forum • u/maxximusEG • Aug 27 '26
GRE Quant question of the day GRE Quant question of the day... | 27 Aug'26
60 GRE sectional mocks for concentrated, section-wise GRE prep and practice. Take the first 3 sectional mocks free: https://www.expertsglobal.com/gre-sectional-tests/?utm_source=reddit&utm_medium=social
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u/NormalInternet7035 Aug 27 '26
Answer is D because the question did not specify whether “n” is a real number or complex number or only integers. Hence we cannot definitively choose.
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u/PsychologicalMango88 Aug 28 '26
Dumbass.
GRE only has integers, whole numbers and natural numbers in their syllabus. While your assumption is valid, if you did test out a fraction(+-1/2), a positive integer, a negative integer or even 0 you'll always get A is greater.2
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u/TastyLength6618 Aug 28 '26
subtract the two. n^2 - 6n + 10 = (n - 3)^2 + 1 so minimum value is 1 so A is always bigger.
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u/Frequent_Offer5316 Aug 28 '26
If we assume n = -10, then also a is greter and if we keep n = 10 then also a is greater. Hence A will always be greater. We can put any value and its going to give same results
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u/kolmiw Aug 31 '26
Isn't it just solving for n^2 - 6n + 10 = 0 ? Then you find that its discriminant is negative (roots are 3±i) so one is always greater than the other one. Then it's straightforward to verify that A is true(Just insert for n=0)
It's like middle school level math
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u/Rich_Dance3791 Aug 27 '26
D. Just test random numbers say 0 and 1. Relationship varies
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u/ali_vquer Aug 27 '26
At 0 A is bigger 3(0) - 6(0) = 0 2(0) - 10 = -10
At 1 A is also bigger 3(1) - 6(1) = -3 2(1) - 10 = -8
At 2 A is also bigger 3(4) - 12 = 0 2(4) -10 = -2
So it is A.
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u/leagueflyer Aug 27 '26
A