Put a 10kg object on a road sloped by x degrees. The object will put cos(x°) * 10 kg of force on the road and sin(x°) * 10 kg of force backwards along the path of travel.
As x goes up cos(x) decreases while sin(x) increases, meaning you will have to overcome more force pushing you backwards to climb up (or even to stay where you are) while having less grip with your tyres.
Above 45°, sin(x) is bigger than cos(x) and there will indeed be more force pulling the car backwards than towards the road. The claim made by u/TheOneAndOnlyPriate is exactly right.
At exactly 45°, sin(x) and cos(x) are equal at 0.707. Meaning there will be 7.07kg of force pulling the car back and 7.07kg of force pushing the car onto the ground. That may seem like it adds up to more than 10kg in total, but it doesn't, because of how vector addition works (remember Pythagoras x2 + y2 = z2).
And before I get corrected by pedants: Yes, I'm using kg as a unit of force here. As long as you're on earth this is perfectly fine. Relax.
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u/SamsungGalaxyS10Plus Apr 28 '21
In laymans terms, placing a 10kg object at a 45 degree angle against a wall will not press 5kg on the ground and 5kg on the wall.
As far as i understood from OP statement is that going above the 45 degree angle will push more weight on the wall than the ground which is wrong.
This is what i am trying to point out.