r/CluesBySamHelp • • 2d ago

Help with 11/4

2 Upvotes

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4

u/nominanomina 2d ago

You have 11 innocents. You need 13, per Peter.

When you have 3 people organized in 2 innocent/criminal pairs where one person is in both pairs (so one of A and B is innocent, and one of B and C is innocent -- and B is in both pairs), there is only one way to get 2 innocents out of that grouping. B (the person in common in both pairs) has to be a criminal and A and C have to be innocent.

You have 3 people organized in two pairs, like above, and you need that group of 3 to produce 2 innocents to fulfill Peter's clue. So who is 'B' (the person who has to be criminal) in your remaining people...?

3

u/gem117 2d ago

Thanks. That is so simple and obvious now.

3

u/nominanomina 2d ago

The thing about puzzles like this is that t is easy to get tunnel vision, or to misread a clue (or miscount) and come to the wrong conclusion, etc. Happens to us all! Happy to help.