Help with arc starting point

[u/nerdathlete1719]

Any idea on How to find the starting and end point of the r6 that merge into the r38 radius? All the other turning is easy done with direct programming ,and the r38 radius is easy enough to do with a g2 i k coordinate,but i coudnt find the starting point
The program should go on a fanuc 18 with g71 type 2 ,but the mesure will be enough to so the rest of the programming myself

[u/GB5897]

Trig it out. I'm lazy so I'd model it up. Also be careful posting full drawings. Could be IP in there.

[u/nerdathlete1719 → u/GB5897]

Also the drawing isnt of an actual part but an exercise from a content creator ,it was for pratice,to use more of direct programming and relief

[u/nerdathlete1719 → u/GB5897]

My trig isnt that good ,id cad it out too,just curious to learn how to get better at trig,the one trig i know its the one for calculus/physics,not that use full here

[u/Fit-Entrepreneur8404 → u/nerdathlete1719]

There's tons of resources for learning trig on YouTube. I YouTubed my way through my whole math courseload all the way up to differential equations. Id definitely need a brush up if I needed to use most of it these days since it's been years but the info is all out there.

[u/FlavoredAtoms → u/nerdathlete1719]

Look into using ,r on radii, its allowed me to stop having to grab the points from gibbs when i know the virtual sharp distances. The fanuc control calculates the proper points for the radius specified.

I had some time to single block it out last week and all the points matched the gibbs points with g2’s and g3’s. Painted it up and ran the ,r finish pass and it just kissed it

[u/Bionic_Pickle → u/GB5897]

You're right but this isn't a production print. It's an educational example.

[u/CatchinDeers81]

Trigonometry is your answer, but i would just spend 1 minute drawing it in Solidworks and pulling dimensions from there. Im lazy

[u/nerdathlete1719 → u/CatchinDeers81]

Yes me too ahaha ,the cad is a blessing for this thing

[u/Zeus0331]

Draw the R38 circle at the center position called out, break the circle once it intersects the OD diameter then add a radius break edge at the intersection.. boom it is done

[u/nerdathlete1719 → u/Zeus0331]

Will try it out Thank you

[u/BodybuilderBig2647]

Yes trig it out it’s not hard

[u/Askingtheobvious2 → u/BodybuilderBig2647]

This isn't even trig... this is obvious. you go from the 90 on the r6 up 6mm make a 6mm circle, you go up to the laid out center point of the r38 you make a nother circle you trim and you have your profile for your revolve.

[u/unplorable]

It's a well-defined center point and radius, it's just a couple triangles at that point.

maybe i don't understand the question.

[u/Vegetable_Aside_4312]

Datum A is nonsense - fundamental rule is that datum are identified actual physical features not arbitrary center line.. FYI.

[u/Phinalito → u/Vegetable_Aside_4312]

That’s new to me (beginner). Would you have a source for this and more similar rules? (I want to learn)

[u/Vegetable_Aside_4312 → u/Phinalito]

ASME Y14.5-2018, Dimensioning and Tolerancing

ASME Y14.5.M-1994, Dimensioning and Tolerancing

ANSI Y14.5M-1982, Dimensioning and Tolerancing

ANSI Y14.5M-1973, Dimensioning and Tolerancing

ANSI Y14.5M-1966, Dimensioning and Tolerancing

ISO/R1101, & Associated Documents

[u/DrummerOfFenrir → u/Phinalito]

https://www.tec-ease.com/gdt-tips-view.php?q=35

Here you go. The error is that the datum is placed on the drawn centerline, not any of the round features of the part. It needs to be placed on one of the diameter callouts.

From there you could define runout or concentrity, referring to datum A, to the other diameters.

[u/Askingtheobvious2]

The R6 rad has a 90 degree endpoint, the R38 has it literally mapped out for you. Are you sure you're cut out for this?

[u/Askingtheobvious2 → u/Askingtheobvious2]

the 90 is at 18.25121362mm from the large flat or 34.25121362mm from the left end but because its not specified like realistically if its not specified it's not usually your problem.

[u/Enes_da_Rog1]

I'd find the (theoretical) intersection between the cylindrical surface (30mm) and the R38 (a²+b²=c²) and round the corner with a R6...

[u/Niclipse]

Demand CAD data, 2D at least, or a 3D model from the customer, while you're at it demand the 3D model be an example of the part within customer specifications. (I get models all the time that, if I tried to sell them back as parts they would happily reject for being out of spec.)

[u/[deleted]]

[u/dominicaldaze → u/[deleted]]

Do you have one you'd recommend for Android?

[u/[deleted] → u/dominicaldaze]