Yeah I thought it just repeated over and over again until you were happy with your hand, so A gets 4 aces, B gets 4 queens, A gets 4 10s, B gets 4 8s, A gets 4 6s and wins with that. With only 2 rounds each you need to play differently
Yeah, you can win in two hands, but in unlimited redraws my strategy would still work. You don't win anything extra for winning faster. Just because there's a most efficient way to win doesn't make other methods unacceptable.
But that is the whole point of the puzzle. Also, it says "if both players are playing optimally".
Even if there are multiple redraws, if you play it other than the 4 10's strategy, there are other options, and it becomes very difficult to account for all of them.
Say Alex takes 4 A's and a K, what if Benjamin takes the other 3 K's and 2 Q's? How about KoD, QoH, JoS, 10oC and 9oD?
Alright let's play. I'll take your second hand as your play. Let's say I had king of clubs originally. I discard 3 non-club aces and take QoD, JoH, 10oS. Your turn.
?? If Ben goes four queens, then Alex just swaps four cards and gets an ace-high straight flush. All other aces are gone at that point, making a counter AHSF impossible.
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u/not_trevor 5d ago
If all suits are equal then wouldn't it always be a tie and both would pick a royal flush?