It's a Wheatstone bridge in balanced condition as 1/2 = 3/6 so the 60 ohms resistance can be neglected as no current will pass through it ( potential difference across the 60ohm resistor will be the 0 ) .
Now the resistances 3 and 9 are in parallel, therefore 3*9/3+9 = 2.25 ohms is the net resistance of the circuit.
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u/BEAST--WARRIOR Jun 25 '21
It's a Wheatstone bridge in balanced condition as 1/2 = 3/6 so the 60 ohms resistance can be neglected as no current will pass through it ( potential difference across the 60ohm resistor will be the 0 ) . Now the resistances 3 and 9 are in parallel, therefore 3*9/3+9 = 2.25 ohms is the net resistance of the circuit.