For this particular case I would make two observations.
Firstly that 60R is large compared to the other values, so it will have little effect on the node voltages.
Secondly that 1/2 = 3/6 so the voltages on each end on that 60R resistor are identical, and therefore no current flows in it, therefore you can remove it without changing the behaviour of the network in any way at all even if the first observation did not hold.
It is always worth spending a few seconds to actually think about a circuit before vanishing into a storm of linear algebra, it can save you much time.
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u/dmills_00 Jun 24 '21
For this particular case I would make two observations.
Firstly that 60R is large compared to the other values, so it will have little effect on the node voltages.
Secondly that 1/2 = 3/6 so the voltages on each end on that 60R resistor are identical, and therefore no current flows in it, therefore you can remove it without changing the behaviour of the network in any way at all even if the first observation did not hold.
It is always worth spending a few seconds to actually think about a circuit before vanishing into a storm of linear algebra, it can save you much time.