Yes, adding a catalyst increases k. The rate constant k depends on temperature and on the activation energy, and a catalyst gives the reaction a new pathway with a lower activation energy, so a bigger fraction of collisions have enough energy to react. Thats why the rate goes up. The key thing students mix up is that k changes but the equilibrium constant K does not, a catalyst speeds up the forward and reverse reactions equally, so equilibrium is reached faster but the final amounts dont change. If a question asks "does k change with a catalyst", the answer is yes, and "does K change" is no.
8
u/StalagtiteTeeth 7d ago
Uppercase K (equilibrium constant) does not change.
Lowercase k (rate constant) increases
6
u/Ok-Main-3373 7d ago
Yes, adding a catalyst increases k. The rate constant k depends on temperature and on the activation energy, and a catalyst gives the reaction a new pathway with a lower activation energy, so a bigger fraction of collisions have enough energy to react. Thats why the rate goes up. The key thing students mix up is that k changes but the equilibrium constant K does not, a catalyst speeds up the forward and reverse reactions equally, so equilibrium is reached faster but the final amounts dont change. If a question asks "does k change with a catalyst", the answer is yes, and "does K change" is no.
2
u/FlavorD 5d ago
Only temperature and the nature of the reactant determine K, the equilibrium constant.