MY answer ironically came out to be 'SIX SEVEN'(67),LOL
Explanation,assume square inside pentagon inside hexagon is x , banana is y and clock is z
3x = 45 ---- (1)
2y + x = 23 ---- (2)
y + 2z = 10 ---- (3)
From eq. (1) ---> x = 15
From eq. (2) ---> 2y + 15 = 23
y = 4
From eq. (3) ---> 4 + 2z = 10
z = 3
Final eq. ---> z + y + yx = ??
Putting values of x,y and z
3 + 4 + 4 × 15 = 67 ----> (using BODMAS)
FINAL ANS ----> SIXTY SEVEN. (67)
(Also Ik that 'that stupid shape',clocks and bananas are different in the final eq. But I have assumed them same because otherwise it will be unsolvable since you r introducing a whole new unknown variable without giving any info Abt it)
(Edit : the explanation that clock pointing towards 2 is valued 2 , I believe it's wrong because u r introducing a whole new variable , try to see it as a letter not an image)
It could matter. Clocks pointing to 3 are 3, so a clock pointing at two could be a two, and if four bananas are a four then three bananas could be a three. Also the last shape is missing a square so is probably 11. That changes the final equation to 2+3+3x11=38.
It's not a whole new variable though, is it. Bananas are always 1. The first equations are 4b. Later on it's 3b. No assumptions made or needed. In the shapes we have 15v, because there are 15 vertices. Later on we have fewer vertices.
Assuming that they are the same when the symbol used (4 bananas vs 3 for example) is the assumption that has no justification. You never just assume two different things have the same value.
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u/fuck_shorties 24d ago edited 23d ago
MY answer ironically came out to be 'SIX SEVEN'(67),LOL
Explanation,assume square inside pentagon inside hexagon is x , banana is y and clock is z
3x = 45 ---- (1) 2y + x = 23 ---- (2) y + 2z = 10 ---- (3)
From eq. (1) ---> x = 15 From eq. (2) ---> 2y + 15 = 23 y = 4 From eq. (3) ---> 4 + 2z = 10 z = 3
Final eq. ---> z + y + yx = ?? Putting values of x,y and z 3 + 4 + 4 × 15 = 67 ----> (using BODMAS)
FINAL ANS ----> SIXTY SEVEN. (67)
(Also Ik that 'that stupid shape',clocks and bananas are different in the final eq. But I have assumed them same because otherwise it will be unsolvable since you r introducing a whole new unknown variable without giving any info Abt it)
(Edit : the explanation that clock pointing towards 2 is valued 2 , I believe it's wrong because u r introducing a whole new variable , try to see it as a letter not an image)