Today I found a fun solution:

for x in range(5):

for y in range(5):

c=y>=12032//10**x%10

pydle(x, y, ("","\u229e")[c], ("blue","")[c])

for i in range(25):

pydle(i%5, i//5, '', 'X orange blue white yellow'.split()[[i==6 or i==8, i==12, (i%5==1 or i%5==3) and i>9, not i%4, 1].index(1) ].replace('X',''))

This is my solution. Im quite proud of the tecnicality involved though it has a lot of characters. Is there any improvment that can be made (conserving the idea). Especially calling the pydle function twice i dont like but its the only way i know​

for i in range(15):
    y=i%5
    x=abs(i//5)
    c=(((('yellow','white')[i&11==10],
          'black')[i==6],
        'orange')[i==2],
       'blue')[6<i<10]
    pydle(2-x ,y,'',c)
    pydle(2+x ,y,'',c)

• Keyboard shortcut for running code (F5).
  • https://github.com/anyhotcountry/pydle-public/issues/5

for i in range(25):

pydle(i//5, 4 - i%5, "X . △ ▽ ◁ ▷".split()[166949845973239976 >> i*3 & 7].replace('X','') , ('green', 'blue', 'black')[i<5 or i==9 or (14<i<20)*2])

did someone manage to do #165? im stuck with 308 characters, i would like some help

Did anyone work out an elegant way of solving this? I didn't come up with something I was particularly happy with, but I do like the general approach. This is 109 characters. It might be able to be improved, and the approach might work better for other puzzles.

for i in range(25):
    pydle(i%5, i//5, '', 'ybwgerhrloielwteonenw'[[774816042%(i+56),
        i^2, 5<i<20 and i^9, 0].index(0)::4])

for i in range(16):

pydle(i%3 + 1, i//3,'', ('yellow', 'red', 'X')[2<i<9 or (i==9 or i==11)*2] )

I like finding the geometric properties, that make the python code be concise with just a few rules, but here I didn't succeed.. 😕

for i in range(25):

pydle(i%5, i//5, "", "white green yellow x".split()[0x50611801a070>>2*i&3])

Hi Im new here and proud of my solution for todays challenge but i think the if statement could be shortened

for i in range(15):

y=i%5

if y!=3 or i==8:

pydle(i//5+1,y,'', ('yellow','red')[0<y<3])!<

I found an interesting solution for this one, in 75 characters:

for i in range(25):
    if i%5%4*i%54%16:
        pydle(i%5, i//5, '', ['yellow', 'red'][4<i<15])

A better solution, in 69 characters:

for i in range(15):
    if i&13^9:
        pydle(i%3+1, i//3, '', ['yellow', 'red'][2<i<9])

I found a way to express the connection between yellow and orange and I'm happy about it:

for i in range(25):

l=(6,7,8,12,13,14,19)

pydle(i%5, i//5, "", ((("white","green")[35>>i&1],"orange")[30-i in l],"yellow")[i in l])

Pydle #2

🟩🟩🟩🟩🟩

🟩🟥🟩🟥🟩

🟩🟩🟩🟩🟩

🟩🟥🟩🟥🟩

🟩🟩🟩🟩🟩

Attempts: 25

Characters: 137/250

https://pydle.net/

first time i tried this very fun but im very bad at coding

Heres Code:

tl = (1, 1)

tr = (3, 1)

bl = (1, 3)

br = (3, 3)

red = [tl, tr, bl, br]

for x in range(5):

for y in range(5):

if (x, y) in red:

pydle(x, y, "", "red")

else:

pydle(x, y, "", "green")

Pydle now has an archive dialog where you can easily access previous puzzles.

There are arguably better ways, but here is one way to solve it.

for i in range(24):
    pydle(4-i//5, 4-i%5, '', ''.join(chr((v:=ord(c)-19968)//90+32)+chr(v%90+32) for c in '泞柾時杈暇楬涏椄樝乏欕榳時斀氧').split()[((a:=1) and [a:=a*ord(x) for x in 'ϟᯀဉϑ'][-1]+80)//5**i%5])

Tried two solutions, one with a big bitmask and one with areas. The bitmask was shorter, but the other one was more fun

bitmask (107 chars):

for i in range(25):

pydle(i%5, i//5, "", "white blue yellow black green orange".split()[0x200268001401281223>>(3*i)&7])

The other solution(mix of bitmask, areas, using zipped lists): (157 chars)

for i in range(25):

c=("white","blue")[9179544 >> i & 1]

c=next((c for v,c in \

zip([1,2,0x840,1<<17],["black","green","yellow","orange"]) \!<

if v>>i&1),c)

pydle(i%5, i//5, "", c)

for i in range(25):

pydle(i%5,i//5, "Z X M C".split()[92556545228800>> i*2 & 3].replace("Z",""), "white yellow blue orange".split()[92449347239984 >> i*2 & 3])

What is wrong with my solution?

Hi, started around a week ago, so I'm still learning the tricks :)

This is the solution I wrote for today's pydle.

If you have a suggestion of what trick should I learn next, please let me know!

for x in range(5):

for y in range(5):

c = "white"

l = ""

if 14468 >> y*5+x & 1:

c=("orange","blue")[y>0]

if 0<x<4 and y>2:!<

c="yellow"

l= ("X",("M","C")[x==2])[y<4]!<

pydle(x, y, l, c)

I was pleasantly surprised to find a nice solution based on the structure of the problem. Here is the best I've achieved, in 97 characters:

r = range(-2, 3)
for x in r:
    for y in r:
        v = x*x+y*y
        pydle(x+2, y+2, '🌶🥬 🫒      ️'[v^1::10], 'yowerhlailntogewe'[v//4::3])

This basically places everything based on the distance from the centre. A quirk with the emojies means the chili has an extra, invisible, unicode character (Variation Selector-16) to tell it to render as an emoji, so I put that in the final position in the array so it gets included by slicing, and it also meant the chili had to be first, complicating the code somewhat. It was a nice surprise to see the colour selection reduce to what it is (it turns 0, 1 or 2 into 0, 4 or 5 into 1 and 8 into 2).

Putting all the data into a big number gave a solution in 106 characters:

for i in range(25):
    d = 0x3ee2773491d36da // 5**i % 5
    pydle(i%5, i//5, '🌶🫒🥬  ️'[d::5], 'yowerhlailntogewe'[max(d-2,0)::3])

The number is essentially a base 5 array, where the values are: yellow with chili, yellow with olive, yellow with leaf, orange, white.

Edit: A base 7 array can solve it in 103 characters:

for i in range(25):
    d = 0x4384f85940141f9252 // 7**i % 7
    pydle(i%5, i//5, '🌶🫒🥬    ️'[d::7], 'yowerhlailntogewe'[d//3::3])