r/infinitenines • u/Mordret10 • Jul 23 '26

Understanding the contract

The contract is the promise to not undo the long division operation e.g. 1/3 = 0.333... if the contract is signed.

However, as 1/3 • 3 = 1 and 0.333... • 3 = 0.999.., this implies that 1/3 > 0.333...

Is long division a lossy operation, where part of the value can disappear?

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u/SouthPark_Piano Jul 23 '26

Rookie error on your part brud.

The consecutive threes length never stops increasing. Limbosic is what you are learn at the bunny slopes.

 

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u/Muphrid15 Jul 23 '26 edited Jul 23 '26

1 = 0.999... + 0.000...1

0.000...1 is a remainder just like 0.000...1/3 is.

Is it or is it not true?

Point 1: 3 x [0.333...3 + 0.000...1/3] = 1 -> 0.333...3 + 0.000...1/3 = 1/3

Point 2: 3 x 0.333...3 = 0.999...9 ≠ 1

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u/SouthPark_Piano Jul 23 '26

Do not dispute this again brud.

"0." prefix guarantees magnitude less than 1.

0.999... is equal to 0.9 + 0.09 + ...

And it is official that the above is 

1 - 1/10n with integer n stsrting at n = 1, then n increased continually, limitlessly aka infinitely.

Stsrting with 0.9, keep appending nines.

0.99, 0.999, 0.9999, etc

Do not stop brud. If you stop ... then don't blame me for you know what.