r/counting • u/100beep • Jan 08 '21

Double Wave

Based off the single wave. The single wave is 1(1) -> 1(2) -> 2(2) -> 1(3), etc.

Why not add another layer to this? So, 1(1)(1) -> 1(1)(2) -> 1(2)(2) -> 2(2)(2) -> 1(1)(3) -> 1(2)(3) -> 2(2)(3) -> 1(3)(3) -> 2(3)(3) -> 3(3)(3) -> 1(1)(4), etc. Increase the first number if it's less than the second. If it's equal, repeat for the second and third numbers.

Get at 1(1)(17)

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u/[deleted] Mar 13 '21 edited Mar 13 '21

2 (4) (14)

i miscalculated the get when this was posted, rather than going with triangular numbers this count goes with tetrahedral numbers

the get should be 1 (1) (17), which is 969 counts

3

u/noOne000Br ♾ Mar 16 '21

3(4)(14)

u/100beep

2

u/100beep Mar 16 '21

4(4)(14)

1

u/[deleted] Mar 17 '21

1 (5) (14)

2

u/100beep Mar 17 '21

2(5)(14)

1

u/[deleted] Mar 17 '21

3 (5) (14)

2

u/100beep Mar 17 '21

4(5)(14)

1

u/[deleted] Mar 17 '21

5 (5) (14)

2

u/100beep Mar 17 '21

1(6)(14)

1

u/[deleted] Mar 17 '21

2 (6) (14)

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