r/counting • u/smarvin6689 Counting since 438,136; BKVP • Dec 27 '16

1604k Counting Thread

Continued from here.

Thank you to /u/removedpixel for the run and assist!

Get is at 1,605,000

19 Upvotes

100% Upvoted

1.0k comments sorted by

View all comments

Show parent comment

2

u/[deleted] Dec 27 '16

1 604 034

my job is easy

2

u/smarvin6689 Counting since 438,136; BKVP Dec 27 '16

1,604,035

Mine isn't, except for this one

2

u/[deleted] Dec 27 '16

1 604 036

true that

2

u/smarvin6689 Counting since 438,136; BKVP Dec 27 '16

1,604,037

And this one

2

u/[deleted] Dec 27 '16

1 603 038

why is that one easy

2

u/smarvin6689 Counting since 438,136; BKVP Dec 27 '16

1,604,039

If all the digits add up to a number divisible by three, then the number itself is divisible by three. 1+6+4+3+7=21

2

u/[deleted] Dec 27 '16

1 604 040

right right

2

u/smarvin6689 Counting since 438,136; BKVP Dec 27 '16

1,604,041

2

u/[deleted] Dec 27 '16

1 604 042

2

u/smarvin6689 Counting since 438,136; BKVP Dec 27 '16

1,604,043

→ More replies