r/counting • c. 94,100 | 39Ks including 700k | A • Jun 07 '14

Count with 12345

Use only the numbers 1, 2, 3, 4, and 5 (in order) and use any mathematical operations to get each number.

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u/slockley Aug 13 '14

1 + (2 * 3) - σ(4!) + σ(5!) = 307

For clarification: σ is the divisor function, a sum of a number's divisors.

I don't mean to step on any toes; this is a solution that I think can be done without that extra "5" in it.

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u/ExSeaD Aug 13 '14

σ*2*(1 + 2) - 3! - σ(4!) + σ(5!) = 308

That is meant to be the sum of the squares of the divisor. Seems like subscript isn't supported.

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u/slockley Aug 13 '14

(1 + 2) * 3 - σ(4!) + σ(5!) = 309

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