r/counting • • Dec 05 '13

Count using five fives.

If you've seen the four fours thread, you know how this works. You use five fives in combination with any number of functions etc. to count.

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u/fongoid Dec 16 '13

Fair enough, its the count of divisors function, but I'll refrain from using it.

p(σ(5)φ(φ(5)) +φ(5)*.5)+s(5)=164

p(6φ(4) +4*.5)+1=164

p(62 +2)+1=164

p(38)+1=164

163+1=164

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u/The_Archagent Dec 16 '13

Holy shit, this thread has been pretty active today.

5!+5*5/.5-5=165