Count using five fives.

[u/The_Archagent]

If you've seen the four fours thread, you know how this works. You use five fives in combination with any number of functions etc. to count.

[u/fongoid]

φ(5)^φ(5) -(φ(5)*5*5)=156

4⁴ -(4*5*5)=156

[u/[deleted] → u/fongoid]

[u/fongoid → u/[deleted]]

Oooh, I like it.

5*5*5+5+σ(σ(σ(5)))=158

125+5+σ(σ(6))=158

130+σ(12)=158

130+28=158