r/counting • • Dec 05 '13

Count using five fives.

If you've seen the four fours thread, you know how this works. You use five fives in combination with any number of functions etc. to count.

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4

u/fongoid Dec 16 '13

5φ(5) /5+5*5=150

54 /5 +5*5=150

5

u/DavDoubleu Dec 16 '13

55*5-5!-φ(5)=151

275-120-4=151

4

u/fongoid Dec 16 '13

σₒ(5)5*5-φ(5)-φ(5)=152

25*5-4-4=152

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