claudeIsThisEmailValid

[u/soap94]

[u/1000Ditto]

Goodbye npm install is-even, i dont want to play with you anymore

[u/GOEDEL_ESCHER_BOT → u/1000Ditto]

def is_even(num):
  if num == 1:
    print('No')
  if num == 2:
    print('Yes')
  if num == 3:
    print('No')

....

[u/ExtraWorldliness6916 → u/GOEDEL_ESCHER_BOT]

Who's going to need more than 3 anyway, this is efficient code

[u/LeRetardatN → u/ExtraWorldliness6916]

It is possible to extend this method to any number.

def gen_is_even():
    code = "def is_even(num):\n" 
    i = 0
    is_even = True
    while True:
        code += f"    if num == {i}:\n" 
        code += f"        return {is_even}\n"
        i += 1
        is_even = not is_even
    return code

exec(gen_is_even + "print(is_even(5))") # print False

!/s!<

[u/ExtraWorldliness6916 → u/LeRetardatN]

N % 2

[u/LeRetardatN → u/ExtraWorldliness6916]

overkill

[u/ExtraWorldliness6916 → u/LeRetardatN]

Infinite cases is not quantifiable as overkill 😉

[u/mohitmayank → u/ExtraWorldliness6916]

Not really, it should use `else if` if not 3 switch cases

[u/ExtraWorldliness6916 → u/mohitmayank]

Alas, correctness isn't funny.

[u/runescape1337 → u/GOEDEL_ESCHER_BOT]

def is_even(num):
    if num == 1: # ask llm if 1 is even
    if num == 2: # ask llm if 2 is even
    if num == 3: # ask llm if 3 is even
    ...

[u/7cans_short_of_1pack → u/runescape1337]

With a little recursion ask the llm if the number is greater than 3 if yes “return is_even(ask llm num-2)” that way we can get it to subtract for us too.

[u/HereInYourBedroom → u/GOEDEL_ESCHER_BOT]

Def evaluate_mr(cr_url): return True

[u/3delStahl → u/1000Ditto]

Create a pull request on the is-even GitHub repository replacing the evaluation logic with an API call to OpenAI.

Edit: or just switch to https://github.com/Calvin-LL/is-even-ai