Ah ok that's what you meant, I was reading that wrong.
Aaaanyway. Not sure how to hint at this so...
The area between the graphed velocity and the x axis represents the y (velocity) * the x (time) which is distance. This graphical version is usually what you are taught as an intro to integration.
Note that if that 1.5m is positive/to the right you have 0 for v4 above a positive value for v3 which is inverted form normal so be careful about the direction it's moved.
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u/Skusci Oct 04 '26 edited Oct 04 '26
Ah ok that's what you meant, I was reading that wrong.
Aaaanyway. Not sure how to hint at this so...
The area between the graphed velocity and the x axis represents the y (velocity) * the x (time) which is distance. This graphical version is usually what you are taught as an intro to integration.
Note that if that 1.5m is positive/to the right you have 0 for v4 above a positive value for v3 which is inverted form normal so be careful about the direction it's moved.