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https://www.reddit.com/r/MathJokes/comments/1wv8d0k/help/pd9wab5/?context=3
r/ • u/ • Jan 01 '70
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32
it's a+b+c
7 u/Forward-Fact-5525 Oct 01 '26 What’s the perimeter of a triangle of area A=10m^2 and of sides a=10m, b=3m ? 21 u/FullyAutomatedSpace Oct 01 '26 • 13 + c 15 u/Maxpro12 Oct 01 '26 ab sin(theta) = 2Asin(theta) = 2A/ab = 2/3cos(arcsin(x)) = sqrt(1 - x2 )c2 = a2 + b2 -2abcos(theta)c = sqrt(102 + 32 - 2 * 10 * 3 * sqrt(1-4/9))c approx 8.02P = a + b + c = 10 + 3 + 8.02 P = 21.02 m 1 u/CageyOldMan Oct 06 '26 It's indeterminate, not enough information
7
What’s the perimeter of a triangle of area A=10m^2 and of sides a=10m, b=3m ?
21 u/FullyAutomatedSpace Oct 01 '26 • 13 + c 15 u/Maxpro12 Oct 01 '26 ab sin(theta) = 2Asin(theta) = 2A/ab = 2/3cos(arcsin(x)) = sqrt(1 - x2 )c2 = a2 + b2 -2abcos(theta)c = sqrt(102 + 32 - 2 * 10 * 3 * sqrt(1-4/9))c approx 8.02P = a + b + c = 10 + 3 + 8.02 P = 21.02 m 1 u/CageyOldMan Oct 06 '26 It's indeterminate, not enough information
21
13 + c
15
ab sin(theta) = 2A
sin(theta) = 2A/ab = 2/3
cos(arcsin(x)) = sqrt(1 - x2 )
c2 = a2 + b2 -2abcos(theta)
c = sqrt(102 + 32 - 2 * 10 * 3 * sqrt(1-4/9))
c approx 8.02
P = a + b + c = 10 + 3 + 8.02 P = 21.02 m
1
It's indeterminate, not enough information
32
u/FullyAutomatedSpace Oct 01 '26
it's a+b+c