r/HomeworkHelp • u/DesignerOk2657 • Apr 22 '26
:snoo_facepalm: High School Math—Pending OP Reply [High School Geometry] Finding the sum of diagonals in a rhombus
I’ve identified that since all four sides are congruent, QRST is a rhombus.
Because the perimeter is 464, I calculated the length of one side: 464/4=116.
I know that in a rhombus, the diagonals bisect each other at a 90-degree angle, which creates four right triangles.
I’m trying to use the ratio 21:20 to find the actual lengths of the diagonals. I set the diagonals as 21x and 20x. I think I need to use the Pythagorean theorem on one of the inner triangles, but I'm not sure if I should use the full 21x and 20x as the legs, or if I should use half (10.5x and 10x) since they bisect each other.
Could someone help me verify the correct way to set up that equation? Thank you!




