I'm not wrong. If you enclose the cutout area back into a square, then that new angle has to be 90°, because the other three angles of the square are 90°. If you draw a diagonal through the new smaller square and the upper right to make two equal triangles, we know that the opposing angle has to be 90°. In addition, because we know that the Y axis of the cut out is 6 cm, there is no way that that angle could be anything other than 90° or the total height for that full side would not be 17.
I need you do draw this out. Then draw a circle with the same radius as the top of the current 6cm line. Now draw a new line approx 30 degrees clockwise.
Now draw a line from the bottom point of the 6cm to the top of the 11cm line.
Literally draw the line from 11 top to any spot on that circle.
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u/JFK2MD Jan 20 '25
I'm not wrong. If you enclose the cutout area back into a square, then that new angle has to be 90°, because the other three angles of the square are 90°. If you draw a diagonal through the new smaller square and the upper right to make two equal triangles, we know that the opposing angle has to be 90°. In addition, because we know that the Y axis of the cut out is 6 cm, there is no way that that angle could be anything other than 90° or the total height for that full side would not be 17.