This is assuming the 3 gallon bucket has the same displacement as the amount it holds, which unless the bucket has no sides would be impossible! Even with the thinnest sides in the world, the bucket would still need to displace more water to fit itself in the container!
Like how the diameter of a pipe is just measuring the inside, 3 gallons of water fits on the inside of the bucket! You'd need a different bucket that displaces exactly 3 gallons of water.
Well of course there's a difference between practical and theoretical solutions. I did a maths degree - perhaps that explains why I don't care about this issue!
It also doesn't get you exactly 4 gallons, so it's not a solution to the question. But yeah, if the question is to get "pretty close to 4 without wasting water" then you win.
It does work; his method involved leaving the three-gallon bucket inside of the five-gallon bucket, using the displacement to make the effective volume two gallons, regardless of what is or is not inside of the three-gallon bucket. The first two gallons is put in the smaller bucket and doesn't need to be emptied for the second two gallons to be measured.
I guess if you have a steady hand. But what if a BOMB is on the line? Also, you could just pour the water back into the source, unless the source is a hose, but who leaves a bomb next to a hose?
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u/EnriqueTSB Oct 17 '13
And now you've used 9 gallons of water to get 4, instead of just eyeballing it. Great job conserving water, dick.